Journal of Indian Acad. Math.  
ISSN: 0970-5120  
Vol. 47, No. 1 (2025) pp. 169-180  
R. Ponraj1  
VECTOR BASIS S-CORDIAL LABELING  
OF FRIENDSHIP GRAPH, FAN GRAPH,  
AND LILLY GRAPH  
and  
R. Jeya2  
Abstract: Let  
basis . Let :V(G) S be a map. For each xy assign the label  
x,y , where x,y denotes the inner product of x and y. We say that  
G
be a (p,q) graph. Let  
V
be an inner product space with  
S
is  
a
vector basis S-cordial labeling if |x y | 1 and  
|i j | 1 where  
x  
denotes the number of vertices labeled with the  
vector x and  
i  
denotes the number of edges labeled with the scalar i. A  
graph with a vector basis S-cordial labeling is called a vector basis  
S-cordial graph. In this paper, we investigate the vector basis S-cordial  
labeling of certain graphs like friendship graph, fan graph, lilly graph,  
bistar  
graph,  
crown  
graph  
and  
armed  
crown  
graph  
where  
S = {(1,1,1,1), (1,1,1,0), (1,1,0,0), (1,0,0,0)} is a basis inR4  
.
Keywords: Friendship Graph, Fan Graph, Lilly Graph, Bistar Graph, and  
Crown Graph.  
Mathematics Subject Classification (2020) No.: 05C78.  
1. Introduction  
In this paper, we consider only finite, simple and undirected graph  
170  
R. PONRAJ AND R. JEYA  
G (V(G)  
,
E(G)) where V(G) and E(G) respectively, denote the vertex set and  
edge set of G. Note that p |V(G)| and q |E(G)|denote the number of vertices  
and edges of G respectively. The idea of graph labeling was first introduced by Rosa  
in 1967 [16]. Vertex odd graceful labeling has studied in [5]. Baskar Babujee and  
Shobana [3] have examined the prime and prime cordial labeling for some  
special graphs. Radio geometric mean labeling of some star like graphs have  
investigated in [8]. Parmar [18] proved that for the wheel, fan and friendship graphs  
are edge vertex prime.  
The join G1 G2 [6] of two graphs G1 and G2 is defined as the graph whose  
vertex set is V(G1)V(G2) and the edge set consists of these edges which are in G1  
and in G2 and the edges contained by joining each vertex of G1to each vertex of G2  
The fan graph Fn [18] is a graph that is constructed by joining all vertices of a path  
to a further vertex, called center. That is,Fn K1 Pn . Amutha and Uma Devi  
.
P
n
[1] have explored the super graceful labeling for some families of fan graphs.  
Barasara [2] proved that the comb is an edge and total edge product cordial. For a  
dynamic survey on graph labeling, we refer to Gallian [6].  
The friendship graph C3(n)[6] can be constructed by joining n copies of the  
cycle graph C3 with a common vertex, which becomes a universal vertex for the  
graph. The corona G1 G2 [6] of two graphs G1 and G2 is obtained by taking one  
copy of G1 and |V(G1)| copies of G2 and joining each vertex of the ith copy of  
G2 to the ith vertex of G1  
.
The concept of cordial labeling was first introduced by I. Cahit [4]. Mitra and  
Bhoumik [11] have introduced the tribonacci cordial labeling of graphs. Parthiban  
and Sharma proved that the Lilly graph is a prime cordial graph in [13]. The Lilly  
graph In,n 2 [13] can be constructed by two star graphs 2K1,n,n 2 joining two  
paths 2P ,n 2 with sharing a common vertex. That is,In 2K  
2Pn . For the  
n
1,n  
terminologies and different notations of graph theory, we refer the book of Harary [7]  
and of algebra; we refer the book of Herstein [9]. Sum divisor cordial labeling of  
theta graph was examined by Sugumaran and Rajesh in [17]. Difference cordial  
labeling for plus and hanging pyramid graphs have studied in [12]. Prajapati and  
A. Vantiya have proved that the triangular snake, double triangular snake,  
quadrilateral snake, double quadrilateral snake are SD-prime cordial in [14]. Kaneria  
VECTOR BASIS S-CORDIAL LABELING OF FRIENDSHIP GRAPH  
171  
et al. [10] have investigated the balanced mean cordial labeling and graph operations.  
We have introduced new labeling called vector basis S-cordial labeling in  
[15] and investigated the vector basis vector basis {(1,1,1,1), (1,1,1,0), (1,1,0,0),  
(1,0,0,0)}-cordial labeling behavior of some standard graphs like path, cycle, comb,  
star and complete graph. In this paper, we investigate the vector basis {(1,1,1,1),  
(1,1,1,0), (1,1,0,0), (1,0,0,0)}-cordial labeling of certain graphs like friendship graph,  
fan graph, lilly graph, bistar graph, crown graph and armed crown graph.  
2. Vector basis S-cordial labeling  
Definition 2.1: Let G be a (p,q) graph. Let V be an inner product space  
with basis S. Let :V(G) S be a map. For each xy assign the labelx,y   
,
where x,y denotes the inner product of x and y. We say that  
is a vector basis  
S-cordial labeling if |x y | 1 and |i j | 1 where  
x  
denotes the number  
of vertices labeled with the vector x and  
i  
denotes the number of edges labeled with  
the scalar i. A graph with a vector basis S-cordial labeling is called a vector basis  
S- cordial graph.  
Theorem 2.2: [15] The set S = {(1,1,1,1), (1,1,1,0), (1,1,0,0), (1,0,0,0)} is a  
basis for R4 over R.  
Theorem 2.3: [15] A graph G is vector basis {(1,0),(0,1)}-cordial if and only  
if G is a cordial graph.  
Theorem 2.4: [15] The path  
P
is a vector basis {(1,1,1,1), (1,1,1,0),  
n
(1,1,0,0), (1,0,0,0)}-cordial graph for all n 1  
.
Theorem 2.5: [15] The cycle Cn is a vector basis {(1,1,1,1), (1,1,1,0),  
(1,1,0,0), (1,0,0,0)}-cordial if and only if n 1,2,3 (mod4)  
.
In this paper, we consider the inner product space ꢀꢁ and the standard  
product x,y   x1y1 x2y2 xnyn where x (x1,x2, ,xn)  
y (y1,y2, ,yn) xi yi R  
inner  
,
,
,
.
172  
R. PONRAJ AND R. JEYA  
3. Main Results  
In this section, we consider the basis S = {(1,1,1,1), (1,1,1,0), (1,1,0,0),  
(1,0,0,0)}.  
Theorem 3.1: The friendship graph C3(n) is a vector basis {(1,1,1,1),  
(1,1,1,0), (1,1,0,0), (1,0,0,0)}-cordial if and only if n 0,1,2 (mod4)  
.
Proof: The friendship graph C3(n) is a planar, undirected graph with 2n 1  
vertices and 3n edges. Let V(C3(n)) {u,ui |1 i 2n} andE(C3(n)) {uu2i1  
uu2i,u2i1u2i |1 i n} respectively be the vertex and edge sets of C3(n).Then  
,
|V(C3(n))|p2n1 and |E(C3(n))|q 3n . There are four case arises.  
Case (i): n 0 (mod 4)  
Letn 4k . Then, p 2n 1 8k 1. Next, we assign the vector (1,1,1,1)  
to the vertex u. Assign the vector (1,1,1,1) to the vertices u1,u2, ,u2k . We assign  
the vector (1,1,1,0) to the next vertices u2k1  
,
u
2k2, ,u4k . Then assign the vector  
4k2, ,u6k . Also assign the vector (1,0,0,0)  
6k2, ,u8k  
(1,1,0,0) to the next vertices u4k1  
to the remaining vertices u6k1  
,
u
,
u
.
Case (ii): n 1 (mod 4)  
Let n 4k 1. Then, p 8k 3. Now, we assign the vector (1,1,1,1) to the  
vertex u. So assign the vector (1,1,1,1) to the vertices u1,u2, ,u2k . Assign the  
vector (1,1,1,0) to the next vertices u2k1  
,
u2k2,,u4k . We assign the vector  
(1,1,0,0) to the next vertices u4k1 4k2, ,u6k  
,
u
.
Further, assign the vector  
(1,1,1,0) to the vertexu6k1 . Assign the vector (1,0,0,0) to the vertex u6k2 . Then  
assign the vector (1,1,0,0) to the vertex u6k3 . Finally, assign the vector (1,0,0,0) to  
the remaining 2k 1 vertices u6k4  
,
u
6k5, ,u8k3  
.
VECTOR BASIS S-CORDIAL LABELING OF FRIENDSHIP GRAPH  
173  
Case (iii): n 2 (mod 4)  
Let n 4k 2. Then, p 8k 5. Also, we assign the vector (1,1,1,1) to the  
vertex u. Assign the vector (1,1,1,1) to the vertices u1,u2, ,u2k1 . We assign the  
vector (1,1,1,0) to the next vertices u2k2  
,
u2k3,,u4k2 . Then assign the vector  
(1,1,0,0) to the vertices 4k3,u4k4, ,u6k3  
u
.
Moreover, assign the vector  
(1,0,0,0) to the remaining 2k vertices  
u
6k4,u6k5, ,u8k4  
.
Case (iv): n 3 (mod 4)  
Let n 4k 3. Then p 8k 7 and q 12k 9. If we assign vector  
(1,1,1,1) to the vertex u and we have to assign (1,1,1,1) to the 2k 1 vertices, then  
2k1  
2
4  
2k 1  
2k 1k 1 3k 2, a contradiction. But 4 3k 1 or  
4 k 1 according as the vertex u receive the vector (1,1,1,1) or not. This is a  
contradiction since the size of C3(n) is 12k 9  
.
Clearly the above labeling pattern provides a vector basis {(1,1,1,1),  
(1,1,1,0), (1,1,0,0), (1,0,0,0)}-cordial labeling for the friendship graph C3(n) if  
n 0,1,2 (mod 4)  
.
Theorem 3.2: The fan graph Fn is a vector basis {(1,1,1,1), (1,1,1,0),  
(1,1,0,0), (1,0,0,0)}-cordial if and only if n 0 (mod 4)  
.
Proof: Let V(Fn ) {u,ui |1 i n} and E(Fn) {uui |1 i n}  
{uiui1 |1 i n 1} respectively be the vertex and edge sets of Fn . Then  
V(Fn) p n 1 and E (Fn) q 2n 1. There are four cases arises.  
Case (i): n 0 (mod 4)  
Let n 4k . Then, p 4k 1. Next, we assign the vector (1,1,1,1) to the  
vertex u. Assign the vector (1,1,1,1) to the first k verticesu1,u2, ,uk . Then, assign  
174  
R. PONRAJ AND R. JEYA  
the vector (1,1,1,0) to the next  
k
vertices uk1,uk2, ,u2k . Also, assign the vector  
2k1,u2k2, ,u3k . Moreover, assign the vector  
3k1,u3k2, ,u4k  
(1,1,0,0) to the next vertices  
k
u
(1,0,0,0) to the remaining k vertices  
u
.
Case (ii): n 1(mod 4)  
Let n 4k 1. Then p n 1 4k 2 (k 1)(k 1)k k  
and  
q 2n 1 8k 1 (2k 1) 2k 2k 2k . Clearly, 4 2k 1 or 4 k  
according as the vertex u receive the vector (1,1,1,1) or not. This is a contradiction  
since the size of Fn is 8k 1  
.
Case (iii): n 2 (mod 4)  
Let  
q 8k 3 (2k 1)(2k 1)(2k 1)2k  
according as the vertex u receive the vector (1,1,1,1) or not. We get a contradiction  
since the size of Fn is 8k 3  
n 4k 2  
.
Then p 4k 3 (k 1)(k 1)(k 1)k and  
.
Thus, 4 2k 1 or 4 k  
.
Case (iv): n 3 (mod 4)  
Let n 4k 3. Then p 4k 4 (k 1)(k 1)(k 1)(k 1) and  
q 8k 5 (2k 2) (2k 1) (2k 1)(2k 1). Hence, 4 2k 1 or  
4  
k  
according as the vertex u receive the vector (1,1,1,1) or not. We get a contradiction  
since the size of Fn is 8k 5  
.
Clearly the above labeling method provides a vector basis {(1,1,1,1),  
(1,1,1,0), (1,1,0,0), (1,0,0,0)}-cordial labeling for the fan graph Fn if n 0  
(mod 4)  
.
Example 3.3: The  
following Figure  
1 illustrates  
the  
vector basis  
{(1,1,1,1), (1,1,1,0), (1,1,0,0), (1,0,0,0)}-cordial labeling fan graph F4  
.
VECTOR BASIS S-CORDIAL LABELING OF FRIENDSHIP GRAPH  
175  
Figure 1  
Vector basis {(1,1,1,1), (1,1,1,0), (1,1,0,0), (1,0,0,0)}-cordial labeling of F4  
.
Theorem 3.4: The Lilly graph In is a vector basis {(1,1,1,1), (1,1,1,0),  
(1,1,0,0), (1,0,0,0)}-cordial graph for all n 2  
.
Proof:  
Consider  
the  
Lilly  
graph  
In, n 2  
.
Let  
V(In) {u,ui,vi |1 i n 1}  
{xi, yi |1 i n}  
and  
E(In) {uxi, uyi |1 i n}{uv1,uu1,uiui1,,vivi1 |1 i n 2} respectively  
be the vertex and edge sets of In . Then and  
.
V(In) p 4n 1  
E(In) q 4n 2  
First, we assign the vector (1,1,1,1) to the vertex u. Assign the vector  
(1,1,1,1) to the vertices u1,u2, ,un1. Then, assign the vector (1,1,1,0) to the  
verticesv1,v2, ,vn1 . Also, assign the vector (1,1,0,0) to the vertices x1, x2, , xn  
. Moreover, assign the vector (1,0,0,0) to the vertices y1, y2, , yn  
.
Hence, the above labeling technique provides a vector basis {(1,1,1,1),  
(1,1,1,0), (1,1,0,0), (1,0,0,0)}- cordial labeling for the Lilly graph In  
.
Example 3.5: The following Figure 2 illustrates the vector basis {(1,1,1,1),  
(1,1,1,0), (1,1,0,0), (1,0,0,0)}-cordial labeling of Lilly graph I4  
.
176  
R. PONRAJ AND R. JEYA  
Figure 2  
Vector basis {(1,1,1,1), (1,1,1,0), (1,1,0,0), (1,0,0,0)}-cordial labeling of I4  
.
Theorem 3.6: The crown graph Cn K1 is a vector basis {(1,1,1,1),  
(1,1,1,0), (1,1,0,0), (1,0,0,0)}-cordial if and only if n is odd.  
Proof: Consider the crown graph Cn K1 . Let Cn be the cycle  
u1u2 unu1. Let  
and E(Cn K1) E(C)  
V(Cn K1) V(Cn){vi |1 i n}  
{uivi |1 i n} respectively be the vertex and edge sets of Cn K1 . Then  
|V(Cn K1)| p 2n and |E(Cn K1)| q 2n . We have considered the two  
cases.  
Case (i): p 0 (mod 4)  
Let p 4k . To get the edge label 4, the vector (1,1,1,1) should be assigned  
to the consecutive vertices of Cn K1 . As the size of Cn K1 is 2n p 4k , the  
maximum edges with label 4 is k 1, a contradiction arises.  
Case (ii): p 2 (mod 4)  
Let p 4k 2. Then, assign the vector in the following order  
u1, u2, un, v1, v2, vn . We assign the vector (1,1,1,1) to the first k 1 vertices  
u1, u2, , uk1 . Also, assign the vector (1,1,1,0) to the next k vertices  
VECTOR BASIS S-CORDIAL LABELING OF FRIENDSHIP GRAPH  
177  
uk2, uk3, , un . We assign the vector (1,1,0,0) to the k 1  
vertices  
v1, v2, , vk1. Moreover, assign the vector (1,0,0,0) to the next k vertices  
vk2, vk3, , vn  
.
Thus, the above labeling technique provides a vector basis {(1,1,1,1),  
(1,1,1,0), (1,1,0,0), (1,0,0,0)}-cordial labeling for the crown graph Cn K1  
.
Theorem 3.7: The armed crown graph ACn is a vector basis {(1,1,1,1),  
(1,1,1,0), (1,1,0,0), (1,0,0,0)}-cordial if and only if n 1,2,3 (mod 4)  
.
Proof: The armed crown graph ACn is the graph obtained from the cycle  
u1u2 unu1 with V(ACn) V(Cn){vi, wi |1 i n} and E(ACn) E(Cn)   
{uivi, viwi |1 i n}respectively be the vertex and edge sets of ACn . Then  
V(ACn) p 3n and E(ACn) q 3n . We have considered the four cases.  
Case (i): p 0 (mod 4)  
Let p 4k . To get the edge label 4, the vector (1,1,1,1) should be assigned  
to the consecutive vertices of the graph.ACn As the size of ACn is 3n p 4k  
,
the maximum edges with label 4 is k 1 , a contradiction.  
Case (ii): p 1(mod 4)  
Let p 4k 1. Then, assign the vector in the following order u1,u2, un  
,
v1,w1,v2,w2, vn,wn . We assign the vector (1,1,1,1) to the first k 1 vertices.  
Next, assign the vector (1,1,1,0) to the next k vertices. Also assign the vector  
(1,1,0,0) to the next k vertices. Further, assign the vector (1,0,0,0) to the remaining k  
vertices.  
Case (iii): p 2 (mod 4)  
Let p 4k 2. Then, assign the vector in the following order u1,u2, un  
,
178  
R. PONRAJ AND R. JEYA  
v1,w1,v2,w2, vn,wn . Now, assign the vector (1,1,1,1) to the first k 1 vertices.  
So assign the vector (1,1,1,0) to the next k vertices. Next, assign the vector (1,1,0,0)  
to the next k 1 vertices. Finally, assign the vector (1,0,0,0) to the remaining k  
vertices.  
Case (iv): p 3 (mod 4)  
Let p 4k 3. Then, assign the vector in the following order u1,u2, un  
,
v1,w1,v2,w2, vn,wn . Also, assign the vector (1,1,1,1) to the first k 1 vertices.  
Assign the vector (1,1,1,0) to the next k vertices. Then, assign the vector (1,1,0,0) to  
the next k 1 vertices. Moreover, assign the vector (1,0,0,0) to the remaining k 1  
vertices.  
Therefore, the above labeling method provides a vector basis {(1,1,1,1),  
(1,1,1,0), (1,1,0,0), (1,0,0,0)}-cordial labeling for the armed crown graphACn  
.
Theorem 3.8: The bistar graph Bn,n is a vector basis {(1,1,1,1), (1,1,1,0),  
(1,1,0,0), (1,0,0,0)}-cordial graph for all n.  
Proof:  
Let  
V(Bn,n) {u,u,ui,vi |1 i n}  
and  
E(Bn,n) {uv,uui,vvi |1 i n} respectively be the vertex and edge sets of Bn,n  
.
n,n  
Note that V(B  
) p 2n 2 and E(Bn,n) q 2n 1. We have considered  
the two cases.  
Case (i): p 0 (mod 4)  
Let p 4k . Next, we assign the vector (1,1,1,1) to the vertices u and v.  
Assign the vector (1,1,1,1) to the vertices u1,u2, ,uk2. Then, assign the vector  
(1,1,1,0) to the vertices uk1,uk, ,u2k2 . Also, assign the vector (1,1,0,0) to the  
next k vertices v1,v2, ,vk . Moreover, assign the vector (1,0,0,0) to the remaining k  
vertices.  
VECTOR BASIS S-CORDIAL LABELING OF FRIENDSHIP GRAPH  
179  
Case (ii): p 2 (mod 4)  
Let p 4k 2. Now, we assign the vector (1,1,1,1) to the vertices u and v.  
Assign the vector (1,1,1,1) to the vertices u1,u2, ,uk1 . Next, assign the vector  
(1,1,1,0) to the vertices uk,uk1, ,u2k1. So, assign the vector (1,1,0,0) to the  
next k vertices v1,v2, ,vk . Further, assign the vector (1,0,0,0) to the remaining  
vertices.  
Clearly the above labeling method provides a vector basis {(1,1,1,1),  
(1,1,1,0), (1,1,0,0), (1,0,0,0)}-cordial labeling for the bistar graphBn,n  
.
4. Conclusion  
Vector basis {(1,1,1,1), (1,1,1,0), (1,1,0,0), (1,0,0,0)}-cordial labeling  
behavior of certain standard graphs like friendship graph, fan graph, lilly graph, bistar  
graph, crown graph and armed crown graph have been investigated in this paper. The  
investigation of different kinds of families of graphs for existence of vector basis  
S-cordial labeling is an open problem.  
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International Journal of Mathematics and Statistics Invention, Vol. 5(8), pp. 23-29.  
1. Department of Mathematics,  
(Received, December 23, 2024)  
Sri Paramakalyani College,  
Alwarkurichi - 627412, Tenkasi dt, Tamilnadu, India  
E-mail: ponrajmaths@gmail.com  
2. Research Scholar, Reg. No. 22222102092010,  
Department of Mathematics,  
Sri Paramakalyani College, Alwarkurichi-627412, Tamilnadu, India  
(Affiliated to Manonmaniam Sundaranar University, Abhishekapatti,  
Tirunelveli - 627012, India)  
E-mail: jeya67205@gmail.com